By William G. Pariseau
""... sufficiently huge and deep in its assurance of rock mechanics suggestions utilized to mine layout to deserve a spot at the bookshelf of each mining geotechnical engineer, and within the library at each mine site.""
From: IJRMMS forty four (2007), 1172 - 1176
summary:
""... sufficiently extensive and deep in its assurance of rock mechanics recommendations utilized to mine layout to deserve a spot at the bookshelf of each mining geotechnical engineer, and within the library at each mine site.""
From: IJRMMS forty four (2007), 1172 - 1176
Read or Download Design Analysis in Rock Mechanics, Second Edition PDF
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Extra resources for Design Analysis in Rock Mechanics, Second Edition
Example text
6 ft of hole per 1/2-in. strand of 36,000 lbf steel when a bond strength of 450 psi is assumed. The bond considered is between rock and grout. A 10-strand assemblage in a 4-in. diameter hole would require about 6 ft of anchorage length. Because progressive failure of the bond is possible, additional length should be provided. Higher strength strands would require additional anchorage lengths. Thus, about one to two feet of anchorage length per strand may be needed. In this regard, specialists in cable bolting surface excavations recommend pullout tests to determine what anchorage length is satisfactory at a given site because rock strength also affects bolting effectiveness.
Seismic force S is an inertia force that is considered to act horizontally and directed away from the slope into the excavation. Magnitude of S is related to weight by a seismic coefficient as that is a decimal fraction of the acceleration of gravity g. 2. 9) where m and a are slide mass and acceleration, respectively. 10. Determine the maximum face angle in consideration of this seismic loading. Solution: The free body diagram now has a horizontal load S that represents seismic loading in a quasistatic manner.
A potential failure surface is inclined 35◦ (α) from the horizontal. Cohesion c of the failure surface is estimated to be 300 psi, while the friction angle φ is estimated to be 30◦ . Specific weight γ of the block is 150 pcf. Determine the slope safety factor FS when the water table is below the slope toe. Solution: Sketch and then draw a free body diagram of the slide mass. H = 600 45° 35° S N W Sketch Free body diagram By definition FS = R/D, R = N tan(φ) + C, R = forces resisting, N = normal force, N = W cos(α), W = γV, D = forces driving, C = cA, cohesive force, A = H / sin(α), V = volume.