By Lars Wåhlin, Lars Wahlin
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Additional info for Deadbeat Universe: A Textbook On Cosmology, Gravitation, Time, Relativity And Quantum Physics, 2nd edition
The importance of absolute energy and relative energy can be further emphasized by the following example. Consider the absolute amount of energy E abs = 9 × 1011 Joules required to launch a 2000 kg rocket to a velocity of vabs = 30 km/s. Adding another 9 × 1011 Joules to the rocket while in flight, through the rocket’s own propulsion system, will increase the velocity by a factor of two (disregarding the weight loss of spent fuel). 4 or more exactly 2 . Why the difference? e. the energy added in flight also includes the extra amount of energy the fuel itself had gained during the launch of the rocket, while in the second case the extra energy is simply increasing the amount of absolute energy at the launch.
This means that we can only observe a small fraction of the Universe from our vantage point in space at x 0 . The small circle around x 0 in Fig. 4a, outlines the horizon of our most powerful telescopes of today. A one cycle (critically damped) Universe dissipates all its potential energy to radiation (8) over one period of oscillation (5), which means that all matter will vanish before reaching the center. This would be analogous to an electron dissipating its potential energy to radiation while falling towards the atomic nucleus.
Velocities generated relative to us by ΔE or ∇E must be added or subtracted to our absolute velocity c by vector summation. For energy gained, the velocity relative to x 0 becomes 2 Δv = c 2 − vabs , (l/t) (4a) (l/t) (4b) and in cases where energy is lost 2 ∇v = vabs − c2 . For example, the velocity of a particle that has gained energy in a particle accelerator by a the amount of ΔE is 2 ⎛ E0 ⎞ ⎟⎟ , Δv = c − ⎜⎜ c E + Δ E ⎝ 0 ⎠ (l/t) 2 (5) which gives the same result as Einstein’s Equation (2). When ΔE is much smaller than E 0 , Equation (5) can be reduced to Δv ≈ c 2 2ΔE , E0 (l/t) (6) and replacing E 0 with Einstein's E 0 = m0 c 2 leads to Newton's familiar v≈ 2E or E ≈ 12 m0v 2 , m0 ( ml 2 / t 2 ) (7) where m0 is mass of matter at relative rest with respect to x 0 .